Germanio: efficienza vs energia

prova inglese numero 1)
The study of the detector’s efficiency can be very interesting in our experiment: gamma rays are uncharged, so they can travel in the detector for long distances before they interact; for this reason we need a relation between the number of incident photons and the number of detector’s counts. We analized ²³²Th’s spectra to study the dependence of HpGe detector's efficiency versus Energy. We define the relative efficiency as:

EFF_rel=N/I

Where N is the number of counts obtained by the gaussian peak’s integration and I is the relative intensity of the line (from http://atom.kaeri.re.kr/).

We have fitted ²³²Th’s datas with the following linear function (Knoll, “Radiation Dectection and Measurement”):

og(eff) = A + B log (E/E0)

(questa formula e la precedente le ho scritte con microsoft equation ma non riesco a copiarle...beh l'importante è che si capiscano)

As we can see from image XXX, (in which we put E₀=1Kev), the best efficiency has been obtained for the lowest Energy.

peggio di fiorini....